Accumulators Solar Panel Ratio
We would need the fewest accumulators if we would just draw power from them if solar panels would produce no power at all.
Accumulators solar panel ratio. 20 regular solar panels or 8 advanced solar panels combined with 14 20 0 7 accumulators gave a stable 1 4mw for 35 sentinels 35 20kw 1 4mw. So for 2 1mw this works out to 50 solar panels and 42 accumulators exactly. The amount of solar panels and accumulators you need is more. We could do that the other way around.
The useful capacity depends on the type of accumulator and the working conditions but it usually has values from 30 to more than 90 in good quality alkaline batteries of the maximum capacity. Or we can say we need 25 solar panels per 21 accumulators. And each cycle the accumulator charge goes from 0 to 100 and back to 0. The optimal ratio is 0 84 21 25 accumulators per solar panel and 23 8 solar panels per megawatt required by your factory this ratio accounts for solar panels needed to charge the accumulators.
If they don t last the night build more batteries. Then when both of those are met build some more. 500 21 p mw solar panels 20 p mw accumulators these are the numbers i use. Just divide if you need a decimal.
The ratio doesn t matter nearly as much as people seem to think it does. Now you have enough for a while. I tried it out in sandbox mode with krastorio 2 and it seems correct. Anyway here s the source.
Or we can say we need 21 25 0 84 accumulators per solar panel. A close enough ratio is 20 24 1 accumulators to solar panels to megawatts required for example a factory requiring 10 mw can be approximately. If your batteries can t fully charge during the day build more solar. Alternatively this works out to a ratio of 25 solar panels to 21 accumulators.
So the result is we need 25 21 1 190476 period 6 more solar panels than accumulators. A single solar panel outputs an average of 42 kw over a day and requires 0 84 accumulators to sustain a constant power output through the night. So the op post is 100 accurate. Reverse operation ratio from decimal needs multiplication and reduction by the largest common divisor.
600 mj capacity of accumulators.